[Fwd: Re: [Cst-1b] FEC/ARQ protocol]

[Phebe Mann]

I got 500 microseconds also delay

Phebe

On Fri, 26 May 2000, M.Y.W.Y.B. wrote:

> 
> --On Freitag, 26. Mai 2000, 19:13 +0100 "Nathan Dimmock" <ned21@cam.ac.uk>
> wrote: 
> [...]
> > so average time to send a packet successfully without errors...
> > 
> > without FEC =  time1 = (1000/d1 + lamda) * 1/p1
> > with FEC = time2 = (1000/d2 + lamda) * 1/p2
> > 
> > you then say what happens when the two times are equal:
> > 
> > time1 = time2
> > 
> > and solve for lamda where the two systems give the same throughput (or
> > whatever)
> [...]
> 
> I did it almost the same way, however,  
> round trip time != delay. 
> 
> In your formula, lambda = round trip time. What we are looking for is the
> delay = lambda/2.
> 
> Did you also get delay = 0.5 ms?
> 
> 
> Moritz
> 
> 
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