[Fwd: Re: [Cst-1b] FEC/ARQ protocol]

[M.Y.W.Y.B.]

--On Freitag, 26. Mai 2000, 19:13 +0100 "Nathan Dimmock" <ned21@cam.ac.uk>
wrote: 
[...]
> so average time to send a packet successfully without errors...
> 
> without FEC =  time1 = (1000/d1 + lamda) * 1/p1
> with FEC = time2 = (1000/d2 + lamda) * 1/p2
> 
> you then say what happens when the two times are equal:
> 
> time1 = time2
> 
> and solve for lamda where the two systems give the same throughput (or
> whatever)
[...]

I did it almost the same way, however,  
round trip time != delay. 

In your formula, lambda = round trip time. What we are looking for is the
delay = lambda/2.

Did you also get delay = 0.5 ms?


Moritz