[CST-2] Kolmogorov complexity - cost of sorting
Anthony Jones
amj30@cam.ac.uk
Fri, 31 May 2002 17:26:09 +0100
On Fri, May 31, 2002 at 05:15:11PM +0100, James Sutherland wrote:
> > well you need O(n) integers, but each one is O(log n) bits long....
>
> Yes, but you are still sorting in O(n) time. The existence of a working
> O(n) algorithm does rather damage the chances of "proving" the hypothesis
> that you can't sort in less than O(n log n) time :-)
And exactly which algorithm can sort a list of ARBITARILY LONG integers in
O(n) time?
Ant
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