[CST-2] Comp. Sys. Modelling

[Alvin]

Hmm I just got the answers off the sample solutions he gave at the examples
class.  I guess you can say that balanced systems with K = 1 still bound the
throughput of the system, which gives U = 1, thus the throughput is just the
reciprocal.

Alvin

> But that doesn't take into account N or K, which I think it needs to as
> you'll need to queue for other customers to finish with the device
> you're waiting for first - it's taken into account in the notes when it
> considers the optimistic/pessimistic cases like you said, so we get  X =
> N/(N+3) x 1/Dav or 1/Dmax.
> 
> There must be more to it than that, I can't believe that inverting two
> numbers is worth 7 marks...
> 
> Cheerio,
> 
> Chris
> do something lastminute.work
> 
> Chris Applegate
> Room X6, Corpus Christi College, Cambridge, CB2 1RH
> chris@qwghlm.co.uk / www.qwghlm.co.uk / [Redacted by SRCF sysadmins on request]
> ICQ 41706821          PGP key available on request
> 
> 
> 
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