[CST-2] Inf. Th. & Cod.

[George van den Driessche]

AFAICT, the PSD is the Fourier transform of the square of the signal. How is
that "flat", if the signal is Gaussian? Surely the square of the Gaussian is
another Gaussian, in which case the Fourier transform is yet another
Gaussian?

Or are we talking about the PSD of white noise with Gaussian distribution?
If so, is it true to say that it is the whiteness of the noise that
guarantees the flatness of the PSD, which is independent of the Gaussian?

I'm confused.

George

----- Original Message -----
From: "David Singleton" <dps29@cam.ac.uk>
To: <cst-2@srcf.ucam.org>
Sent: Tuesday, May 28, 2002 8:19 PM
Subject: RE: [CST-2] Inf. Th. & Cod.


>
> It's their Power Specral Density which is flat...
>
> David
>
> --
> David Singleton    _________________      St John's College, Cambridge
>  C5 3rd Crt        +44(0)7980 641608  http://www.davidsingleton.co.uk/
>
> > -----Original Message-----
> > From: cst-2-admin@srcf.ucam.org [mailto:cst-2-admin@srcf.ucam.org]On
> > Behalf Of Matej Pfajfar
> > Sent: 28 May 2002 20:08
> > Cc: cst-2@srcf.ucam.org
> > Subject: [CST-2] Inf. Th. & Cod.
> >
> >
> > Forgive the stupid question - but could someone please explain to me why
> > Gaussians have a flat fourier power spectrum (as in one of the
questions)?
> >
> > I thought they have gaussian fourier spectra?
> >
> > Thanks.
> >
> > Matej Pfajfar
> > St John's College, University of Cambridge, UK
> >
> > GPG Public Key @ http://matejpfajfar.co.uk/keys
> > Most people are good people, the rest of us are going to
> > run the world. -- badbytes
> >
> > WARNING: THIS E-MAIL ACCOUNT WILL BE DELETED ON
> >          15/07/2002. PLEASE USE mp@cantab.net.
> >
> >
> >
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