[CST-2] CSM 98.9.3?

eycc2@cam.ac.uk eycc2@cam.ac.uk
Mon, 28 May 2001 19:45:09 +0100


I've already written to Tim Harris about the solution to this question
yesterday.  This is the reply I got from him this morning:
--------------------------------------------------------------
I'll try to post a full answer this afternoon but the basic result
is that the departure process will be the same as the arrivals
process: both exponential and with the same parameter.  (If the
system is not overloaded).

I didn't do the proof this year but you might notice the
relationship between this result and the brief section on Jackson's theorem
towards the end of the slides.

Tim
--------------------------------------------------------------
So hopefully, we'll get an answer from Tim Harris soon.  If not, I'll ask him
again tomorrow.
E.


Andrei Legostaev wrote:

> I'm not convinced by Nathan's explanation...
>
> Unless I'm very confused a sum of exponentially distributed variables
> Gamma-distributed.
>
> At the same time there is a simple reason why the *rates* of
> arrival/departure are the same: if they weren't then the system would not be
> in equilibrium.  As far as I understand we only deal with stable systems in
> this course (time-dependent Chapman-Kolmogorov aside).
>
> Has this question generated enough confusion for us to ask TLH?
>
> A
>
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