[Cst-1b] numerical analysis 98/3/10

[spj23@cam.ac.uk]

hi

i was just wondering about the answer to the first one - this is how i
thought you did it...

it's a normalised number as it's 1.x so we don't worry about 
the 1 as it's taken care of in the hidden bit.

0.125 is an eighth, ie 2^-3, so in total we get 2^(-3-31) = 2^(-34)
we store exponents as e + eMAX, so store the exponent as -34+127 = 93
so _I_ THINK the answer is
0 for the sign bit
93 in binary for the exponent
0 for the significand

??? thanks