[Cst-1b] Complexity - the EXP class
Matthew Richards
mwr22@cam.ac.uk
Sat, 27 May 2000 18:56:43 +0100
I think EXP is the class of languages that can be accepted by a
deterministic machine in exponential time.
As for the proof that PSPACE (= EXP [ '(=' is supposed to be 'is a subset
of'... ]: We already know PSPACE (= NPSPACE. We can show NPSPACE (= EXP by
using an argument similar to the one in the notes for NL and P:
NSPACE(n^k) (= TIME(k^(log n + n^k)) from the Reachability algorithm.
k^(log n + n^k)
= (k^log n).(k^(n^k))
= (n^log k).(k^(k^n))
= (n^a).(b^n) (where a=log k and b=k^k)
which is exponential in n. Hence NPSPACE (= EXP => PSPACE (= EXP.
I have no idea if that's the proof Dr Dawar intended, but it seems to work.
Matthew
-----Original Message-----
From: cst-1b-admin@srcf.ucam.org [mailto:cst-1b-admin@srcf.ucam.org]On
Behalf Of Martin Harper
Sent: Saturday, May 27, 2000 6:19 PM
To: CST-1B@srcf.ucam.org
Subject: [Cst-1b] Complexity - the EXP class
Help, please...
Slide 36 says that PSPACE is contained in EXP.
great! but what's EXP!? And given that the preceding two slides were all
about
simulating a non-deterministic machine, where does this fit in, given that
PSPACE is defined on deterministec machines?
Thanks,
Martin.
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